Aufgabe 0f146

$3x^2= 48$

$\frac{1}{4}x^2= 1$

$-\frac{2}{3}x^2= -\frac{3}{8}$

$\frac{1}{2}x^2= 0$

$5x^2 = 180$

$\frac{1}{4}x^2 = 400$

$4x^2 = -24$

$12x^2 =972$

$x^2 +5= 30$

$x^2 -8= 56$

$x^2 +25= 16$

$x^2 -\frac{1}{7}= \frac{29}{49}$

$x^2 - 15 = 34$

$x^2 - \frac{9}{49} = 0$

$x^2 - 64 = 0$

$x^2 + 9 = 0$